The specific conductance of 0.01M solution of KCl is 0.0014per ohm cm at 25^°C .It's equivalent conductance is
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A conductivity cell was filled with a 0.02M KCl solution which has a specific conductance of 2.768 × 10^-3 ohm^-1 cm^-1 . If its resistance is 82.4 Ω at 25 ^o C the cell constant is:
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The specific conductance of a 0.01 M solution of KCl is 0.0014 ohm^-1 cm^-1 at 25^∘C . Its equivalent conductance is.
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SOLVED: The electrical resistance of a column of 0.05 M NaOH solution of diameter 1 cm and length 50 cm is 5.55 × 103 ohm. Calculate its resistivity, conductivity and molar conductivity.
Given the ionic equivalent conductivities for the following ions : lambda^∘eqK^⊕ = 73.5 cm^2 ohm^-1 eq^-1 lambda^∘eqAl^3 + = 189 cm^2 ohm^-1 eq^-1 lambda^∘eqSO4^2 - = 85.8 cm^2 ohm^-1 eq^-1 The Λ^∘eq
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